Any ideas area appreciated, thank you for reading. Though I think when the radius of the circle is equal to or less than the width of the rectangle the area covered should be 100% (in this case, am I correct?). So I'm not sure how to account for this (and to be honest don't understand why this is happening). The semi-circle has a radius of 5 and its area can be found by halving the area formula of a circle: The total area of the composite figure is the sum of all its parts: A 86.6 + 40 + 39.3 122. The area of the semi-circle is one-half the area of a circle. With a rectangle of $2$ units tall and $0.8$ units wide, using the formula: The length and width of the rectangle are 10 in and 4 in respectively, so its area is. However, I have noticed that when the radius of the circle is very close to half the width of the rectangle, a smaller circle actually means the final percentage value is smaller (which should not be the case, correct?). I made a first post here: Area of Circle Overlapped by Rectangle, where "achille hui" was nice enough to point out a way of calculating this value. Some two-dimensional shapes are not even polygons, like our ellipse, or a circle.This is a question regarding how to calculate the area of a circle occupied by a rectangle when that rectangle is larger than the circle (see this link for a example image ). ![]() Now, we will calcualte the area of the remaining trianagle using the area of a triangle formula:Ī = 1 2 ( 12 i n c h e s × 12 i n c h e s )Īdd these two areas to find the total area in square inches:ġ44.5 i n 2 + 72 i n 2 = 216.5 i n 2 Find the Area of a Circle
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